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v(x,y)=(y^2cos(xy^2)+ye^x, 2xycos(xy^2)+e^x) Find a function f such that v=grad f
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is it not take integral of v?
@cinar
@Zizik v = grad f, it means v = gradient f, right?
yes
v(x,y) = (partial derivative of x, partial derivative of y)
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yes, taking integrals.
\[f=\sin(xy^2)+ye^x\]
\[\int\limits_{}^{}v(x,y)dx=\sin(xy^2)+ye^x+c_{1}(y)\\\ \int\limits_{}^{}v(x,y)dy=\sin(xy^2)+c_{1}(x)\]
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