Question

sin2xcosx-cos2xsinx=-1/2
I get its sin(a-b) I just don't know how to apply it

Answer 1

Well, it looks like that a would be 2x and b would be x in this case. So this is just a difference of sines formula originating from just sin(x). So looks like all you have to do is solve for sin(x) = -1/2

Answer 2

i need to answer for A= and b = though ... i feel like im just overthinking the problem

Answer 3

Well a is just 2x and b is just x. Unless you mean that we need to find sin2x= -1/2 and sinx = -1/2. Otherwise I think you're justoverthinking it.

Answer 4

so A would just be 2B essentially ?

Answer 5

Right. Because the difference of sines is sinAcosB - cosAsinB. So if all you need are A and B, then you just pluck them right from the equation, making A = 2x and B = x. Now if you had to actually solve for x, then you have (sin2x - x) = -1/2: sinx = -1/2

Answer 6

ok thank you very much

Answer 7

Mhm :3