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Use the distance formula and pythagorean theorem to find the distance, to the nearest tenth, between each pair of points 1.) U(0,1) and V(-3,-9)
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distance formula is \[\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\] -3 is x2 0 is x1 -9is y2 1 is y1
thxs! min 2 more?
ill see what I can do
M(10,1) AND n (2,-5)
(10,-1)
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do you have to find the distance between theses as well?
yes please
ok you use the same formula as above 2 is x2 10 is x1 -5 is y2 -1 is y1
im guessing your going to have another pair you use the same formula as above then once you have the distance of all 3 you use the pythagorean theorem \[a ^{2}+b ^{2}=c ^{2}\] c^2 will be the longest distance
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