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Mathematics 13 Online
OpenStudy (anonymous):

Q=c+d divided by 2 for d

OpenStudy (zzr0ck3r):

\[q=\frac{c+d}{2}\\\text{solve for d}\\?\]

OpenStudy (anonymous):

yes

OpenStudy (zzr0ck3r):

multiply both sides by 2 and what do we have?

OpenStudy (anonymous):

2q = 2c+2d ?

OpenStudy (zzr0ck3r):

\[q=\frac{c+d}{2}\\\text{multiply both sides by 2}\\2*q=2*\frac{c+d}{2}\\\text{the 2's cancel on the right hand}\\2*q=\cancel{2}*\frac{c+d}{\cancel{2}}\\2q=c+d\]

OpenStudy (zzr0ck3r):

make sense so far?

OpenStudy (anonymous):

yes . do i need to get anything by itself?

OpenStudy (zzr0ck3r):

now subtract c from both sides and tell me what you have

OpenStudy (anonymous):

2q=d

OpenStudy (zzr0ck3r):

you only subtracted it from the Right Hand Side, you need to do it on both sides

OpenStudy (anonymous):

2q-c=d

OpenStudy (zzr0ck3r):

correct

OpenStudy (anonymous):

thank you so much ! ^_^

OpenStudy (zzr0ck3r):

np

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