Question

can some one help with x^2-21x+38=0

Answer 1

What are we trying to do? Factor or Solve for x?

Answer 2

solve by factoring

Answer 3

Ok. So in order to get x^2 we had to have multiplied to X's right?
(x- )(x- )
Now we need to find two numbers that are factors of 38
1, 2, 19, 38, -1, -2, -19, -38

(x-19)(x-2) <- Seems right, to check just FOIL it and see if it is like your original problem.

Answer 4

why didnt you use + and - @boricua86 just wondering

Answer 5

the answers are 2 and 19. Since the equation is quadratic. You need to find the factors of 38 that when added will be = to -21, Hence the nos. are -2 and -19

Answer 6

The factors will then be (x-19) and (x-2)
Equate each factor to zero, then solve for x

Answer 7

@help123456 Its easier to just go with the - and - because you have -x and a +n so when you multiply two neg numbers you get +. Now for the - you have a number that is a negative in the second term. Most likely that number was negative. Hard for me to explain. Florcelda mentiond how to finish the problem.

Answer 8

ok