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simplify this expression: 2/x-y + 3/x+y - 5/ y-x - 7x-9y/y^2-x^2
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let's all make the denominators in the form of (x + y) and (x - y) 2/(x - y) + 3/(x + y) + 5/(x - y) + (7x - 9y)/ x2 - y2 LCD will be (x2 - y2) or (x + y)(x - y) You are now ready to combine the terms
ok I have the denominator... still confused with the numerator? :/
Ok, {2(x + y) + 3(x - y) + 5(x + y) + (7x - 9y)} (x+y)(x-y)
Ready now to combine the terms in the numerator? But do the distributive property first
Let me refresh you, let's do the first term 2/(x-y) since the LCD is (x-y)(x+y) , it will be the LCD divided by denom (x-y) times num 2 so the first term will become 2(x+y)/(x+y)(x_y) I placed all the num under one denom which is the LCD
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