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how would i find the derivative of cos(x)-xcsc(x)?
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find derivative of cosx, then use uv-vdu for xcscx to get derivative
What is uv-vdu?
integration by parts
@dorky_nefty, if you know the derivative of \(\cos x\), the first term is simple to differentiate. For the second term, \(-x\csc x\), you have to use the product rule. Overall, you have \[\begin{align*}\frac{d}{dx}\left(\cos x-x\csc x\right)&=\frac{d}{dx}\cos x-\frac{d}{dx}x\csc x\\ &=\frac{d}{dx}\cos x-\left(\frac{d}{dx}[x]\csc x+x\frac{d}{dx}[\csc x]\right)\\ \end{align*}\]
looking at this answer above me.. seems wrong LOL
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Okay I think I know what I have to do now thanks :)
You're welcome
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