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The graph of y = 3tan(2x) is shifted to the left by 60 units and down 5 units. Write the new equation.
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@SithsAndGiggles help please
@goformit100 help please
Have you tried writing \(y=3\tan (2x)\) in the general form? \[\large y=3\tan\big(2(x-c)\big)+d\] Horizontal shift left by 60 units means \(c=-60\), and a vertical shift down by 5 units means \(d=-5\).
so the equation would be y= 3tan(2(x-60)-5 ??
@SithsAndGiggles
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Close, it's \(y=3\tan(2(x+60))-5\). The general form contains \(x-c\). A shift left means \(c\) is negative, so you'd have \(x-(-c)=x+c\).
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