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I have done tried to do this one I need help Which of the following is the vertex of the function? y = x2 - 6x + 9 (3, 0) (-3, 36) (4, 1) (1, 4)
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\[y=\left( x-3 \right)^{2}\] t is an upward parabola with vertex (3,0)
thank you can you explain a little more
just plug y=0 andx-3=0
o okay
So, we start with our original equation: y = x^2 - 6x + 9 and come out with this: (x-3)(x-3) which equal (x-3)^2.
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Vertex is (h, j) where y = a(x-h)^2 + j Plug in your numbers in this equation. So your j is zero, and your h is 3.
Giving you your vertex: (3,0).
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