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Mathematics 15 Online
OpenStudy (anonymous):

HEEEEEELLLLPPPP MEEEE!! The equation of a sine function with amplitude of 8 and period 45 degrees is ?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

HELP PLEASE

OpenStudy (radar):

y = a Sin bx That is the general form for a sine function without a phase shift, Your problem does not mention a phase shift. So that is it. The a is for the amplitude........What is the given amplitude?

OpenStudy (anonymous):

also which equation can be used to fin the max value of the s

OpenStudy (anonymous):

8 is the amplitude

OpenStudy (anonymous):

and 45 degrees is the period

OpenStudy (radar):

Yes so we start with y = 8 Sin b x b is for the period and is equal to (2 Pi)/b. Since the period is given as 45 degrees convert that in terms of pi, Here is how I remember how to do that, 180 degrees = 1 Pi, 90 degrees = 1/2 Pi so 45 degrees must be 1/4 Pi since the period = (2 Pi)/b we have this situation:|dw:1377120891543:dw| we now can complete the equation; y=8 Sine 2x

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