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find the vertex of the function given below ? y=x^2-2x+1
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i got i got 1,0
The vertex of any parabola is \[x = -\frac{b}{2a}\] In other words, if you have a = 1 and b = -2, then \[x = -\frac{(-2)}{2(1)}\]
So \[x = \frac{-(-2)}{2} = \frac{2}{2} = 1\]
Now that we know x = 1, we insert that into the equation to find the y value.
yes i got that
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we plug it in
Sorry, I didn't see your first post.
then we got zero
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