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7x+2greater than or equal to 2(2x-4)+3x
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\[7x+2\le2(2x-4)+3x\]
Distribute the 2 to each term in the brackets.\[\Large 7x+2\le 2\cdot2x-4\cdot2+3x\]
So after we multiply those things, I guess that gives us,\[\Large 7x+2\le 4x-8+3x\]
Looks like we can combine some x's on the right side.
so the right side would say 7x-8
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yes :)
what step is next? remember?
then i subtract 7x from bith sides and i got 2ge-8
Oh oh, it's greater than? You used the wrong sign in your equation. Careful there! :)
Or is that the way it's written for you?
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i messed up again its le but my answer would be always true right?
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