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(-9 / 3) / ((-6)^2 / 12) @JoStudy
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OK So is that \[\huge \frac{ -9 }{ 3 }/\frac{ -6^{2} }{ 12 }\]
yepp
OK So rememebr PEDMAS what do you solve first in this equation?
-6^2/12
Ah close but out of that equation which do you solve first?
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-9/3
Think about it pEdmas
\(\Huge \frac{ -9 }{ 3 }/\frac{\color{red}{ -6^{2}} }{ 12 }\)
6^2
-6^2
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-9/3 / -36/12
OK\ \[\huge\frac{ -9 }{3}\ \frac{-36}{12}\]
Do you know how to divide fractions?
did u switch it up??
Yup :) you invert one of the fractions then multiply
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so it would be -9/3 / 12/-6 ??
-9/3 / 12/-36
yep!
\[\huge\frac{ -9 }{ 3 }*\frac{ 12}{ -36 }\]
I got 1
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Exactly!
u make it so much easier
Thanks :) I try to make it understandable :)
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