Question

3^(2x+2)=8

(Exponential and Logarithmic Help)

Answer 1

(2x+2)ln3=ln8

2x+2=ln8/ln3

2x=ln8/ln3-2

x=1/2*(ln8/ln3-2)

Answer 2

Is the base 3?

Answer 3

Hey, here's the solution to 9^(x+1) = 27
Let's express both sides to have the same base
since 9 = 3^2 and 27 = 3^3
we can write the equation as 3^2(x+1) = 3^3
Having the same base we can equate the exponents,
2(x+1) = 3
you can now solve for x

Answer 4

@Florcelda how did you get 27 rhs

Answer 5

3 is not base just ln3

Answer 6

Isn't this the first problem we tried to solve a while ago?

Answer 7

3^(2x+2) = 8 (new problem)
is it really a 3 raised to the power 2x + 2?

Answer 8

can you verify the problem for me?