3^(2x+2)=8

(Exponential and Logarithmic Help)

Question

3^(2x+2)=8

(Exponential and Logarithmic Help)

anonymous · Answer

(2x+2)ln3=ln8

2x+2=ln8/ln3

2x=ln8/ln3-2

x=1/2*(ln8/ln3-2)

anonymous · Answer

Is the base 3?

anonymous · Answer

Hey, here's the solution to 9^(x+1) = 27
 Let's express both sides to have the same base
since 9 = 3^2     and 27 = 3^3
  we can write the equation as 3^2(x+1) = 3^3
  Having the same base we can equate the exponents,
                                                2(x+1) = 3
            you can now solve for x

anonymous · Answer

@Florcelda  how did you get  27 rhs

anonymous · Answer

3 is not base just  ln3

anonymous · Answer

Isn't this the first problem we tried to solve a while ago?

anonymous · Answer

3^(2x+2) = 8  (new problem)
is it really a 3 raised to the power 2x + 2?

anonymous · Answer

can you verify the problem for me?