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Mathematics 18 Online
OpenStudy (anonymous):

Trig Identities

OpenStudy (anonymous):

\[\cot^2x - \tan^2x =1\]

OpenStudy (anonymous):

true or false?

OpenStudy (anonymous):

According to the Pythagorean Identities, \[\tan^2 x + 1 = \sec^2 x\].

OpenStudy (anonymous):

If you move \[\tan^2 x \] to the other side. . . you get : \[\tan^2 x + 1 = \cot^2 x.\]

OpenStudy (anonymous):

I think false, because \[\cot^2x-\tan^2x=1\] turns into \[\cot^2x=\sec^2x\] through Pythagorean identities

OpenStudy (anonymous):

^ Yeah.

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