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In the equation y=0.05x^2-x+1 what are the x and y intercepts
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\[\Large y=0.05x^2-x+1\]The y-intercept shouldn't be too difficult to find. We simply need to plug in x=0 to find it.
For the x-intercepts we'll let y=0 and solve for x.\[\Large 0=0.05x^2-x+1\] We can throw this into the Quadratic Formula, that might be the easiest way.\[\large x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
thank you that is more understandable
ok cool :)
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