Question

6x^2 − 19x + 3 = 0 is 1/6. What is the other solution?

Answer 1

\[6x^2 - 19x + 3 = 0\] is \[\frac{ 1 }{ 6 }\]

Answer 2

lol

Answer 3

6*3 = 18
and
-18+ -1=-19
so
6x^2-19x+3 = 6x^2-18x-x+3 = 6x(x-3)-1(x-3) = (6x-1)(x-3) = 0
so
6x-1=0 implies x = 1/6
and
x-3 = 0 implies x = ?

Answer 4

sorry its late:)

Answer 5

I was a bit confused when you took it off xD

Answer 6

Ok so let me review that one sec...

Answer 7

one zero is \(\frac{1}{6}\) so the factor is \(6x-1\)

Answer 8

OH so you basically just made 2 terms out of -19x right?

Answer 9

put
\[6x^2-19x+3=(6x-1)(something)=0\]

Answer 10

x = 3?

Answer 11

yes

Answer 12

OHHH ok I see it now, after reviewing the..er...scatter zz made :)

Answer 13

the method I used is sometimes called the AC method. you should Google that and practice it. imho

Answer 14

haha no problem I will :)

Answer 15

The thirst for knowledge!