Question

How does one solve this differential equation? y'=e^(t+y), y(0)=0.

Answer 1

Relatively easily, since e^t is constant?

Answer 2

\[e ^{(t+y)}=e ^{t}e ^{y}\]

Answer 3

I think I can solve it by separable equations. Is that right?

Answer 4

Oh, is y = f(t)? The problem statement should say that.

Answer 5

Oops. Yes, f(t)=y.

Answer 6

Well, there you go. Now, it's separable.

Answer 7

Thanks.