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Trigonometry
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How do I find f(g(x)) if f(x) = 3x + 1 and g(x) = x^2 - 1?
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g(DeadShot) = DeadShot^2 - 1 isn't it?
now what is g(f(x))?
so f(g(x)) = 3(g(x)) + 1, right?
YUP
3(x) = 3x+1 So f(g(x)) = 3*g(x) + 1 [Now put g(x)'s value in it] Understood? :D
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\[f(g(x)) = 3*(x^2-1)+1\]
f(x) tells us that the function f, is composed of x f(g) simply tells us that the function f, is composed of g, and we know how g is composed since they tell us that already
So then \[f(g(x))= 3x^2-2\] or \[f(g(x))=3x^3-2\]?
\[f(g(x)) = 3*(x^2-1)+1\] this does not produce an x^3 .... so
so then the answer would be \[3x^2-2\]
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