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What are the zeros of f(x) = x^2 - 5x -24?
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Split the middle term! :)
Getting me?
not quite, do you mean split like x^2 + 1x +1 = (x+1)^2
\[x^2-5x-24=(x+3)(x-8)\] right?
EXACTLY! :D
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so then the zeroes are 3 and -8, right?
Not quite :D If (x+3)(x-8) = 0 then (x+3) = 0/(x-8) = 0 So x = -3 And same for (x_8)!! :D Understood? :)
yes, thanks!
:)
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