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Mathematics 25 Online
OpenStudy (anonymous):

Does anyone know how to use the substitution method with linear equations?

OpenStudy (natalieee):

put up a problem and i'll check it out

OpenStudy (anonymous):

-3x + 4y = -10 x-5y = 7 THIS IS MY TEAM WORK ASSIGNMENT NOT HOMEWORK

OpenStudy (natalieee):

I don't remember , sorry

OpenStudy (anonymous):

I can solve this but I don't know what substitution method is!

OpenStudy (anonymous):

HOW WOULD YOU SOLVE IT?

OpenStudy (anonymous):

From the second equation, solving for \(x\) gives you \(x=7+5y\). Substitute this expression for \(x\) into the first equation: \[-3x+4y=-10~~\Rightarrow~~-3(7+5y)+4y=-10\] Now solve for \(y\), then for \(x\).

OpenStudy (anonymous):

I would multiply the second equation by 3 and then add two equations term by term

OpenStudy (anonymous):

This is so dang confusing!

OpenStudy (anonymous):

well it's the fast way

OpenStudy (anonymous):

Ok, so far I have -11y=11? I am still working on it though.

OpenStudy (anonymous):

Yes, that's correct so far.

OpenStudy (anonymous):

Y= -1?

OpenStudy (anonymous):

Yeah, now plug that into either original equation and solve for \(x\).

OpenStudy (anonymous):

x-5(-1)= 7?

OpenStudy (anonymous):

Does x=2?

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

So that would be the answer for both?

OpenStudy (anonymous):

or is there just 1 answer?

OpenStudy (nurali):

-3x + 4y = -10---(1) x-5y = 7----(2) in equation (2) x=7+5y---(3) put in equation (1) -3(7+5y)+4y=-10 -21-15y+4y=-10 -21-11y=-10 -11y=-10+21 -11y=11 y=-1 put in equation (3) x=7+5(-1) x=7-5 x=2

OpenStudy (anonymous):

Ok, how do you get the x to equal 7+5y in the 1st part?

OpenStudy (nurali):

x-5y = 7 add both side by 5y x-5y+5y=7+5y x=7+5y

OpenStudy (anonymous):

Thank all of ya'll very much! I really appreciate it!

OpenStudy (nurali):

My Pleasure.

OpenStudy (anonymous):

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