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Approximation
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How\[\sqrt {1-\frac{x^2+y^2}{a^2}}\approx(1-\frac{x^2+y^2}{2a^2})\]?
Ever hear of a Binomial Expansion?
ofc. I can show that using binomial theorem?
Yup. The next term would be \(-\dfrac{1}{8}\left(\dfrac{x^{2}+y^{2}}{a^{2}}\right)^{2}\), so the approximation is a little high.
I don't need to show it, I just need to know how can I show it. So, the answer is using binomial theorem?
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Yes, that will do. It is using the Binomial Theorem up to the Linear Term and discarding all higher-order terms.
Thanks
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