1/3 (x-2) = x + 4 HELPPP
where is the problem? you have to solve for x..cross multiply and continue
i have to multiply x-2 by 1/3 right?
@ankit042
distribute the 1/3 through the parenthesis
or you can multiply both the side with 3
true
\[\frac{ 1 }{ 3(x-2) }=x+4\] or \[\frac{ 1 }{ 3 }(x-2)=x+4\] which one?
reply @melissalovee!
the second one @Nurali
ok
@Nurali please let her do it on her own...you can guide her to reach the answer
\[\frac{ 1 }{ 3 }(x-2)=x+4\] \[(x-2)=3(x+4)\] \[x-2=3x+12\] \[3x-x=-12-2\] \[2x=-14\] \[x=\frac{ -14 }{ 2 }\] \[x=-7\]
@Nurali thanks a lot. Is that a rule that instead of distributing the 1/3 you can just multiply the other side by 3?
multiply both sides by 3.
Oh so you are getting rid of the 1/3 basically
Yes
You can do by either way. This is basic algebra, You might find this useful http://www.dragonboxapp.com/
Thanks @ankit042. Learned this back in 7th grade so its hard for me to remember it all.
np :)
yeah that is right
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