Question

Solve system using elimination.
6x+3y=-12
6x+2y=-4

Answer 1

6x+3y=-12
-6x-2y=4
--->
y=-8
and x=???

Answer 2

I'm sorry, I don't understand how you got y=-8.

Answer 3

\[6x + 3y = -12 \rightarrow 6x = -12 - 3y\]\[6x + 2y = -4 \rightarrow 6x = -4 -2y\]now we have 2 equation that one side of them is 6x, so other sides are equal!\[-12-3y = -4 - 2y \rightarrow -3y + 2y = -4 + 12 \rightarrow -y = 8\]so \[y = -8\]
can you continue and solving system?

Answer 4

So if that's how I find the y, do I do the opposite for the X? Like separate the y from the x and normal number?

Answer 5

you should plug in -8 for y and then find x

Answer 6

So 6x-16=-4?

Answer 7

ohom, and 6x = 12 and x =2 ;)

Answer 8

Okay, thank you so much.

Answer 9

yw ;)

Answer 10

\[y=-8 and x=2\]