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8|x+3/4|<2
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You should start by taking the eight and diving it by both sides. What do you get then?
x+3/4<2/8
Now you need to divide 3/4 by 8. This is like diving 8 by 0.75
And by 8 i mean 2/8 which is 1/4
why divide and not subtract 3/4 or 6/8
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XD i saw it as 3/4x. You're right you should subtract 3/4 by 1/4 1/4 - 3/4 = ?
i got x<-1/2 and x<1 but that is not one of my options
\[\Large \left|x+\frac{3}{4}\right|<\frac{2}{8}\]So dropping the absolute brackets gives us,\[\Large -\frac{2}{8}\lt x+\frac{3}{4}<\frac{2}{8}\]Subtracting 3/4 from each side,\[\Large -\frac{2}{8}-\frac{3}{4}\lt x<\frac{2}{8}-\frac{3}{4}\]If you simplify the 2/8's, it should be easier to subtract your fractions.
-1<x<-1/2 Thank you
yay good job \c:/
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