Question

Solve the equation of log (2x + 4) = log (3x -12)
With explanation please.

Answer 1

\[\log(2x+4) - \log(3x-12) = 0\]
\[\log(\frac{2x+4}{3x-12})=0\]
\[\frac{2x+4}{3x-12} = 1\]
2x+4 = 3x-12
-x = -16
x = 16