Question

solve sinx + 2sinxcosx = 0, [0,2pi)

Answer 1

Can you factor something out, so you have a product that is =0?

Answer 2

And if you can, then since AB=0, you know that A=0 or B=0. That will give you 2 simpler equations to solve. :)

Answer 3

?

Answer 4

sinx(1 + 2cosx) =0

Answer 5

is it sinx=0, cosx=-1/2

Answer 6

Those are your equivalent compound equations, yes. :) Now you need to solve each of those. You should get 2 solutions for each one, so 4 total solutions.

Answer 7

pi, 2pi, 2pi/3, and 4pi/3 ?

Answer 8

they want the solutions in the interval [0,2pi)
the ) means up to but not including 2pi. Use 0 instead

Answer 9

thanks

Answer 10

Yeah. You're welcome.