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A=lw+wh+lh, for w
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1. subtract lh from both sides. 2. Factor w out of the right side 3. Divide both sidel by (l+h)
how do you factor out the w on the right side?
A=LW+WH+LH A=W[L+H]+LH A-LH=W[L+H] (A-LH)/[L+H]=W
subtract lh from both sides A-lh = lw+wh factor out the w A-lh = w(l+h) now divide both sides by l+h as @Mertsj suggested
so my answer will be s-lh/l+h = w
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s?
I meant a-lh/l+h=w
correct
Make sure you do not forget the parenthesis, else it'd be wrong *___*
hopefully I won't
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\[A-lh=lw+wh\] \[A-lh=w(l+h)\]
\[(a-lh)/(l+h)=\frac{a-lh}{l+h}\] \[a-lh/l+h=a-\frac{lh}{l}+h\]
\[\frac{A-lh}{l+h}=\frac{w(l+h)}{l+h}\]
\[\frac{A-lh}{l+h}=w\]
you might want to make a note \[l\ne-h\]
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this must hold...
aww okay ..
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