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Mathematics 18 Online
OpenStudy (anonymous):

A=lw+wh+lh, for w

OpenStudy (mertsj):

1. subtract lh from both sides. 2. Factor w out of the right side 3. Divide both sidel by (l+h)

OpenStudy (anonymous):

how do you factor out the w on the right side?

OpenStudy (anonymous):

A=LW+WH+LH A=W[L+H]+LH A-LH=W[L+H] (A-LH)/[L+H]=W

OpenStudy (zzr0ck3r):

subtract lh from both sides A-lh = lw+wh factor out the w A-lh = w(l+h) now divide both sides by l+h as @Mertsj suggested

OpenStudy (anonymous):

so my answer will be s-lh/l+h = w

OpenStudy (zzr0ck3r):

s?

OpenStudy (anonymous):

I meant a-lh/l+h=w

OpenStudy (zzr0ck3r):

correct

OpenStudy (anonymous):

Make sure you do not forget the parenthesis, else it'd be wrong *___*

OpenStudy (anonymous):

hopefully I won't

OpenStudy (mertsj):

\[A-lh=lw+wh\] \[A-lh=w(l+h)\]

OpenStudy (zzr0ck3r):

\[(a-lh)/(l+h)=\frac{a-lh}{l+h}\] \[a-lh/l+h=a-\frac{lh}{l}+h\]

OpenStudy (mertsj):

\[\frac{A-lh}{l+h}=\frac{w(l+h)}{l+h}\]

OpenStudy (mertsj):

\[\frac{A-lh}{l+h}=w\]

OpenStudy (zzr0ck3r):

you might want to make a note \[l\ne-h\]

OpenStudy (zzr0ck3r):

this must hold...

OpenStudy (anonymous):

aww okay ..

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