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Which of the following are rational numbers? A; √3/27 B; 3-27 (I already know this one is rational) C; √3 - √27 D; √3/ √27 E; ( √27+3)( √27-3)
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some gimmick here \[\frac{\sqrt{3}}{\sqrt{27}}=\sqrt{\frac{3}{27}}=\sqrt{\frac{1}{9}}\]
which as you can see is \(\frac{1}{3}\) so pick that one for sure
try multiplying out \[(\sqrt{27}+3)(\sqrt{27}-3)\] and see what you get
So √3/√27 = 1/9 ?
no it is \(\frac{1}{3}\)
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since the square root of 9 is 3
oh ok. and (√27+3)(√27-3) = 39.5884572681199
it is \[27-9=18\]
how?
\[(a+b)(a-b)=a^2-b^2\]
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and so \[(\sqrt{27}+3)(\sqrt{27}-3)=27-9\]
ok i kind of understand. is that all?
yeah i think that is all the rationals ones
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