Question

. If the dielectric constant of a capacitor is decreased, then its capacitance will?

Answer 1

capacitance is directly proportional to the dielectric constant of a capacitor ?

Answer 2

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Answer 3

Capacitance is C=Q/V, or quantity of charge the capacitor holds when there is a certain amount of potential across the capacitor.

Taking parallel plate capacitor and using gauss law, integrating to find V and then taking Q/V, we find that capacitance
\[C=k\epsilon_{0}\frac{A}{d}\]
Where k is the dielectric constant, A is area and d is distance between the 2 plates. Fringing fields are ignored.

When k increases, C increases.