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Mathematics 14 Online
OpenStudy (anonymous):

Please and Thank you!!! Which point lies in the solution set for the following system of inequalities? y > x + 4 y > -2x + 2 (-4, 0) (-3, 2) (2, -1) (0, 6)

OpenStudy (texaschic101):

lets plug in some points and find out... (-4,0) y > x + 4 : 0 > -4 + 4 : 0 > 0 (false) they are equal. No need to do the other equation with these points because they both have to be true. moving on to the next points... (-3,2) y > x + 4 : 2 > -3 + 4 : 2 > 1 (true) y > -2x + 2 : 2 > -2(-3) + 2 : 2 > 6 + 2 : 2 > 8 (false) these points will not work either. You try the next points and see if they are true

OpenStudy (ivettef365):

you can try by substituting the x and y values on the equations to see which one is true

OpenStudy (anonymous):

I think it would be (2, -1) ?

OpenStudy (texaschic101):

are you sure ? plug in the values and see

OpenStudy (anonymous):

Yes i'm sure, unless i did it wrong

OpenStudy (anonymous):

i'm new to this type of algebra

OpenStudy (texaschic101):

y > x + 4 (2,-1) -1 > 2 + 4 -1 > 6 is that true ?

OpenStudy (texaschic101):

is -1 greater then 6 ?

OpenStudy (anonymous):

No >.<

OpenStudy (texaschic101):

(0.6) y > x + 4 6 > 0 + 4 6 > 4 (true) y > -2x + 2 6 > -2(0) + 2 6 > 0 + 2 6 > 2 (true) (0.6) is your solution set

OpenStudy (texaschic101):

do you understand ?

OpenStudy (anonymous):

Kind of sorta, i'm new at this. So i havent really done this before

OpenStudy (texaschic101):

just remember that your solution sets are always (x,y). Just plug them into your inequalities, but remember, they both have to be true, not just one of them

OpenStudy (anonymous):

Okay thank you! :)

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