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Mathematics 21 Online
OpenStudy (anonymous):

Factor 3x^2+11x+6

OpenStudy (anonymous):

use quadratic function..

OpenStudy (anonymous):

More help, please?

OpenStudy (anonymous):

Quadratic formula: http://c3e308.medialib.glogster.com/media/9c/9c086d138ebf82ce79c28f346c00bdea499a80b29a8ebb91f65e97f1fff25b22/quadraticformula.jpg Your given: a=3 b=11 c=6 plug it in the quadratic formula.

OpenStudy (ybarrap):

Try grouping: \(3x^2 + 11x + 6=3x^2 + 9x + 2x +6=3x(x+3)+2(x+3)=(x+3)(3x+2)\)

OpenStudy (anonymous):

I got the answers (-4/6) and -3

OpenStudy (anonymous):

I got the right answers now.

OpenStudy (ybarrap):

Perfect!

OpenStudy (anonymous):

Thanks for the help!

OpenStudy (ybarrap):

yw

OpenStudy (anonymous):

What about 9x^2-25?

OpenStudy (ybarrap):

You should see the 9x^2 as a (3x)^2 and 25 as 5^2 to rewrite your equation as (3x)^2 - 5^2. But why would I do that?

OpenStudy (ybarrap):

a^2 - b^2 = (a+b)(a-b) That's why.

OpenStudy (anonymous):

Okay I will.

OpenStudy (anonymous):

What do I do after I rewrite it?

OpenStudy (ybarrap):

That will be your factors. You can then set (a+b)(a-b)=0. This will be the case when either a=-b or a=b. When you plug in a=3x and b=25, the two answers will just pop out.

OpenStudy (ybarrap):

*I meant b=5, not b=25

OpenStudy (anonymous):

Thanks!

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