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Mathematics 24 Online
OpenStudy (anonymous):

urgent need

OpenStudy (wolf1728):

Okay I've got it worked out and it's all in the attachment.

OpenStudy (tkhunny):

Such a problem is best approached by NAMING the values desired. "what is the average speed of each?" C = Speed of Car #1 D = Speed of Car #2 Now, we can talk about them.

OpenStudy (anonymous):

i didn't get it

OpenStudy (wolf1728):

tkhunny - I didn't solve for either. I solved for the average velocity then I solved for Car A and Car B

OpenStudy (tkhunny):

That's just the start. We have this: C = Speed of Car #1 D = Speed of Car #2 We have more problem statement... " the average speed of the car is 5 km/hr more than that of the other " Just pick one. C = D + 5 km/hr We have more problem statement... "end of 5 hr" Car #2 Travels D * 5 hr = 5D kh/hr Car #1 Travels C * 5 hr = (D + 5 km/hr) * 5 hr = 5D + 25 km How are we doing?

OpenStudy (tkhunny):

@wolf1728 No worries. The OP asked, so I thought I'd try a slightly different approach.

OpenStudy (anonymous):

where does 425 gone

OpenStudy (tkhunny):

Excellent question!! We have more problem statement!!! You knew I was going to say that, right? " they are 425km apart " 425 km = 5D + 5D + 25 km You should be able to solve this for D. Sorry, I wrote " 5D kh/hr" above. That should have been "5D km".

OpenStudy (tkhunny):

Units can be a blessing and a curse. I became a little confused on this one. The numbers should still work out.

OpenStudy (anonymous):

D= 40

OpenStudy (anonymous):

and C = 45 km @tkhunny plse check is it right

OpenStudy (tkhunny):

I believe we have it!

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