Factor x^3 +27?
scary titan.. use formula a^3 + b^3 = (a + b)(a^2 – ab + b^2)
x^3+27 is the same as x^3 + 3^3, so: (x+3)(x^2-3x+9)
Would it be (x^2+9)(x+3)
Okay
Never mind
I'm confused on how you got that answer.
There are some special formulas for factoring sums/differences of cubes. \[\Large a^3 – b^3 = (a – b)(a^2 + ab + b^2)\] \[\Large a^3 + b^3 = (a + b)(a^2 – ab + b^2) \]
So just figure out what your a is and your b is, and then plug & chug in the formula. Here, you have \(\Large x^3+27=x^3+3^3\)
Lol dude, I told you I was correct.
Factoring is my best skill. (x + 3)(x^2 - 3x + 9)
I'm not understanding how you are getting the answer though.
If you read what Debbie said, you can make 27 into 3^3.
Which does affect the factors of this equation to what it looks like.
(x^2+9)(x+3) = x^3 + 9 + 27. That's why that's NOT CORRECT.
With the answer you give me the (x's and 3x^2's cancel each other.
*9x
Do you even know how you factor? If you do, work out the answer you believe to be correct. Lol.
Lol, where did you get 9x?
I can factor really simple problems but I have never factored a problem with x^3.
x^3 = x * x * x
x^3-3x^2+9x+3x^2-9x+27
And the 27=3^3
Lol okay look, you factored wrong. and Why are you wasting time on factors that don't even equal your answer?
I'm just really confused.
4 people have given you the SAME answer, so you should just put that as your answer and watch it be correct. Lol.
I'm wanting to know how to do it though.
Lol. This is a essay question, aint it? Then your gonna copy and paste what I write as your answer.
With all the information already on this question, you can do it yourself.
It's not. I'm just wanting to understand how to solve it.
Read what everyone else put. Then you will UNDERSTAND! (:
mk
you have the formula a^3 + b^3 = (a + b)(a^2 – ab + b^2) So plug in these values a= x b=3 then that is simply the answer
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