Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1002_01/1002_01_03.jpg

OpenStudy (anonymous):

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1002_01/1002_01_03.jpg Given: Square with side c. All four interior triangles are right triangles. All four interior triangles are congruent. The interior quadrilateral is a square. Prove: a2 + b2 = c2 Square with side length c; four right triangles with hypotenuse with length c and legs measuring a and b; the interior quadrilateral is a square. When written in the correct order, the paragraph below proves the Pythagorean Theorem using the diagram. Let a represent the height and b represent the base of each triangle. The area of one triangle is represented by the expression One halfab. (1) The length of a side of the interior square is (a – b). (2) The area of all four triangles will be represented by 4 • One halfab or 2ab. (3) The area of the interior square is (a – b)2. (4) By distribution, the area is a2 – 2ab + b2. The area of the exterior square is found by squaring side c, which is c2, or by adding the areas of the four interior triangles and interior square, 2ab + a2 – 2ab + b2. Therefore, c2 = 2ab + a2 – 2ab + b2. Through addition, c2 = a2 + b2. Which is the most logical order of statements (1), (2), (3), (4) to complete the proof? (2), (1), (4), (3) (1), (2), (3), (4) (1), (2), (4), (3) (2), (1), (3), (4)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!