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Find the intercepts in y =x^2 +3x/(3x+1)^2
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I found the y-intercept. I just need help with finding the xintercept because Im stuck and I dont know what to do next
If you want to know how far I got, I'll type it out. I'm not sure if its correct though
\[0 =(x^2+3x)/(3x+1)^2 \] remove the fraction first and then multiply the sides by the denominator.
So then you have x^2+3x= (3x+1)^2
Then what do you do?
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0 * (3x + 1)^2 = (x^2 + 3x)= 0*[(3x+1)^2] = 0 You can multiply out the denominator, as long as the denominator is not zero, get it?
basically juz cancel out the denominator right? so x=0 or x=-3 ? That's all? @@
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