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How does one factor y^5 - 16y?
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start with \[y(y^4-16)\] and then factor \(t^4-16\) as the difference of two squares
So the final answer is " y(y^2+4)(y^2+4)"?
Sorry, one of those would be a negative 4, yes?
Yes
But the program is telling me that it's wrong... so I understand up to what satellite73 said, but I don't really understand what to do after that. y(y^4-16), now how do I take the perfect square?
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If you see a difference of two squares factor it. (Y^2-4) can be factored
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