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Mathematics 22 Online
OpenStudy (victor_15):

Hi guys. Can anyone kindly help me with this: The number of coins 1.5cm in diameter & 0.2cm thick to be melted to form a right circular cylinder of height 10cm & diameter 4.5cm is?

OpenStudy (anonymous):

I'm assuming as a start that 16.6 coins is the answer.

OpenStudy (anonymous):

I need a formula to work with, tho

OpenStudy (anonymous):

Okay, let's build our own equations for this question. First off, what's a formula that combines between the diameter and the height of a cylinder ?

OpenStudy (anonymous):

a. first determine the final volume of the cylinder b. determine the volume of a single coin c. divide volume of cylinder by volume of single coin in order to determine number of coins required d. round up, although its entirely possible to have a fraction of a coin, no person is will ever be able to cut it exactly. to be on the safe side, write down both answer Volume of cylinder \[V= \pi r^2 h\]

OpenStudy (anonymous):

^ Give this guy more medals!

OpenStudy (victor_15):

No, Four. The options are A.380 B.450 C.472 D.540 Thanks, complete idiot: but, how do i find the volume of a coin?

OpenStudy (anonymous):

whom did you call a complete idiot fam?

OpenStudy (victor_15):

That's his username, right? @Four

OpenStudy (anonymous):

lol ma bad

OpenStudy (victor_15):

Sorry guys, I completely forgot I had a question here. @four. @completeidiot So, I'm guessing 22/7 * r^2 * h = Vol of coin

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