How do you find the range in a function like this:
f(x)= |3x-1|+2
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OpenStudy (debbieg):
Do you know how to do transformations on the absolute value function?
Like, horizontal and vertical shifts?
OpenStudy (anonymous):
|3x-1|is equals 0 at the very least. so the function equals 0+2=2 at the very least so the range is [2, ∞)
OpenStudy (anonymous):
but how do I know that it equals 2 at the very least?
OpenStudy (debbieg):
What is the smallest vale that |anything| can take on?
OpenStudy (debbieg):
*value
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OpenStudy (anonymous):
the absolute value always equals 0 at the very least and 0+2=2
OpenStudy (anonymous):
so |3x-1| =0 ? and then I just add the 2?
OpenStudy (anonymous):
@IBstudent yes dude (:
OpenStudy (anonymous):
my english isn't good, sorry (:
OpenStudy (anonymous):
Thank you :D and your english is alright!!!
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OpenStudy (debbieg):
Do you UNDERSTAND it, @IBstudent ? Do you know what range is? Do you know the connection between range and the graph, and what the graph of this function looks like?