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Mathematics 15 Online
OpenStudy (anonymous):

Simplify the equation and write it in standard form.

OpenStudy (anonymous):

@ekerrick7 equation!!!!!!!!!!

OpenStudy (anonymous):

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OpenStudy (anonymous):

\[x= \frac{12}{(x+3)(x+4)}= \frac{12}{x(x+4)+3(x+4)}= \frac{12}{x^2+4x+3x+12}\] \[x= \frac{12}{x^2+7x+12}\] \[x(x^2+7x+12)= 12 \rightarrow x^3+7x^2+12x= 12 \] \[x^3+7x^2+12x- 12 =0\] Which is the standard form of the given equation.

OpenStudy (anonymous):

@ekerrick7

OpenStudy (anonymous):

thanks so much

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