Question

xsquared+2x-15=0

Answer 1

x2 + (5-3)x - 15 = 0
x2 + 5x - 3x - 15
x(x+5) -3(x+5)
For these types of questions ALWAYS SPLIT THE MIDDLE TERM! :)

Answer 2

Complete it btw! :)
Getting this? :D

Answer 3

Not at all. Where did yoyu get 5-3 in place of 2?

Answer 4

you*

Answer 5

Good question!
To get the 5 and 3!
We rquire this procedure!
Let us say we did NOT know that!
Let p and q be those 2 numbers!
The trick here is that!
p*q should be = 15(In this case) [Which is the last constant term]
And
p+q or p-q should be 2(In this case) [Which is the middle constant term with x]
Getting this? :)

Answer 6

Solve this: x2 + 5x + 6

Answer 7

I have no idea. I can get part of it by just basing it off of what you did for the other one. It also doesn't help I have to keep recovering the webpage and the screen with the problem keeps bouncing all around because of ads or something that keep appearing and disappearing.

Answer 8

Let me solve this for you and see if it helps!
x2 + 5x + 6

STEP 1: Okay so now we need 2 numbers that would give their product as 6
And would give there sum or difference as 5

STEP 2: I think we are safe with 2 and 3
Because they multiply to give 6 and add to to give 5 [YIPPE!]

STEP 3: Let us put this in the expression by splitting the middle terms.

STEP 4:
x2 + (2+3)x + 6
x2 + 2x + 3x +6
x(x+2) + 3(x+2)
(x+3)(x+2)

STEP 5: So the solutions are -3 and -2! :D

Getting this? :)

Answer 9

Ooo. Im starting to. I know how to get the two numbers now. Will those two numbers always be the solution?

Answer 10

Yes the opposite of the 2 numbers!
Like for (x+3)(x+2) the solution is -3,-2
And for your question (x-3)(x+5) the solution is +3,-5
Getting it? :)
Now!
Do this now: x2 + 7x + 12!! :D
Try it come on! :D

Answer 11

x=-3 and x=-4?

Answer 12

EXCELLENT!! :D
See you got it! :D

Answer 13

Alright thanks :)

Answer 14

:)