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OpenStudy (anonymous):
OpenStudy (anonymous):
ya math should be easy this year
OpenStudy (anonymous):
no ones answering
OpenStudy (anonymous):
lmao
OpenStudy (anonymous):
hate this site omg why is no one answering
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OpenStudy (anonymous):
are you doing SAS or wb o wait ur donig sas im gonna ask wb q's
OpenStudy (anonymous):
im done with workbook just 6-9 sas 3
OpenStudy (anonymous):
ivana u dont need to ask wb questions @ivanapen8
OpenStudy (anonymous):
@jim_thompson5910 can u help
OpenStudy (anonymous):
ik but i wanna know how to do them
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OpenStudy (anonymous):
looooooool
jimthompson5910 (jim_thompson5910):
by the HL theorem, we can say that triangle ABF = triangle ABE
so that means
BF = BE
5x = x^2 + 6
0 = x^2 + 6 - 5x
0 = x^2 - 5x + 6
x^2 - 5x + 6 = 0
(x-2)(x-3) = 0
I'll let you finish up
jimthompson5910 (jim_thompson5910):
sorry not the HL theorem, the AAS theorem
but everything else is still the same
OpenStudy (ybarrap):
BE=BF, since AB bisects \(\angle FAE\) and thus, corresponding angles are congruent.
So \(5x=x^2+6\)
Solving for x, yields two solutions: \(x=2\) and \(x=3\)
OpenStudy (anonymous):
so is x 2 or 3?
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