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Mathematics 16 Online
OpenStudy (anonymous):

picture is attatched help

OpenStudy (anonymous):

OpenStudy (anonymous):

ya math should be easy this year

OpenStudy (anonymous):

no ones answering

OpenStudy (anonymous):

lmao

OpenStudy (anonymous):

hate this site omg why is no one answering

OpenStudy (anonymous):

are you doing SAS or wb o wait ur donig sas im gonna ask wb q's

OpenStudy (anonymous):

im done with workbook just 6-9 sas 3

OpenStudy (anonymous):

ivana u dont need to ask wb questions @ivanapen8

OpenStudy (anonymous):

@jim_thompson5910 can u help

OpenStudy (anonymous):

ik but i wanna know how to do them

OpenStudy (anonymous):

looooooool

jimthompson5910 (jim_thompson5910):

by the HL theorem, we can say that triangle ABF = triangle ABE so that means BF = BE 5x = x^2 + 6 0 = x^2 + 6 - 5x 0 = x^2 - 5x + 6 x^2 - 5x + 6 = 0 (x-2)(x-3) = 0 I'll let you finish up

jimthompson5910 (jim_thompson5910):

sorry not the HL theorem, the AAS theorem but everything else is still the same

OpenStudy (ybarrap):

BE=BF, since AB bisects \(\angle FAE\) and thus, corresponding angles are congruent. So \(5x=x^2+6\) Solving for x, yields two solutions: \(x=2\) and \(x=3\)

OpenStudy (anonymous):

so is x 2 or 3?

jimthompson5910 (jim_thompson5910):

correct, x = 2 or x = 3

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