picture is attatched help
ya math should be easy this year
no ones answering
lmao
hate this site omg why is no one answering
are you doing SAS or wb o wait ur donig sas im gonna ask wb q's
im done with workbook just 6-9 sas 3
ivana u dont need to ask wb questions @ivanapen8
@jim_thompson5910 can u help
ik but i wanna know how to do them
looooooool
by the HL theorem, we can say that triangle ABF = triangle ABE so that means BF = BE 5x = x^2 + 6 0 = x^2 + 6 - 5x 0 = x^2 - 5x + 6 x^2 - 5x + 6 = 0 (x-2)(x-3) = 0 I'll let you finish up
sorry not the HL theorem, the AAS theorem but everything else is still the same
BE=BF, since AB bisects \(\angle FAE\) and thus, corresponding angles are congruent. So \(5x=x^2+6\) Solving for x, yields two solutions: \(x=2\) and \(x=3\)
so is x 2 or 3?
correct, x = 2 or x = 3
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