If m RDC = 120°, then m DAC=? https://media.glynlyon.com/g_geo_2012/7/group179.gif
Anything else given?
Nope
I could really use alot of help though
Given: DR tangent to Circle O. If m C = 63°, then m BDR =? 63? 90? 126? Is it this?
If m RDC = 120°, then m DAC=?? 60? 120?<< This? 240?
C is given as 63' ?
Yes. C=63, do what would BDR equal
so"
So DCB is 63 or OCB is 63' If it is OCB i can help!!!
It only says c=63, so what would BDR =?
does BDR equal 126?
Are you looking for mDAC, or mDAB? @breton
m DAC
Ok...
I'm confused, because there is no angle DAC
in the diagram you gave
oh wait, you are looking for the arc that makes total sense now, right?
You have to construct then! :p
how do you think you might find this arc? @breton
Theres two different questions I asked. 1) Given: DR tangent to Circle O. If m C = 63°, then m BDR =? 2) If m RDC = 120°, then m DAC =? The DAC is the angles. D is at the bottom of the circle. YOu don't see it? https://media.glynlyon.com/g_geo_2012/7/group179.gif
lol, I see it - I didn't receive your first question So let's work on 1) first
Alright! :)
I need to find out what equals BDR. And my choice is 126? I believe this is correct but I don't know if I am 100%
If you have an angle of 90 degrees from the center of your circle, what is the intercepted arc? This is a quarter circle
RDC itself is 120' How can BDR be 126' ?
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You're correct, @breton
It is 126 degrees
any time you have an angle that starts at the center of the circle, the arc will have the same measurement
So then my second question. If m RDC = 120°, then m DAC =? Would this answer be 240?
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