If A = {1, 2, 3, 4, 5, 6, 7, 8, 9} and B = {3, 6, 9, 12, 15, 18}, what is A union B?
make a list if the number is in A, put it in the list if the number is in B, put it in the list just don't repeat any i.e. only put it in once
Okay , So If A & B have say , 3 do i put it in A's side or B's side ?
make a list like this \[\{\text{ stuff goes here}\}\]
there is no "side" it is just a list written like A or like B
the A U B(thats union).is a set that consists of all the elements of A nd B...without repetion of any element...like u have 3 in both the sets...but it must be present only once in the set A U B...got it??
@satellite73 Mmkay .. @amriju not really ._. this is why i hate math .
\[A\cup B=\{\text{ list of numbers }\}\]
so lets go slow, because once you know what it is asking you are going to be 'really is that all?"
\[\{\text{ we are going to put numbers here }\}\]
ok first u yhave to understand that for set A nd set B ... A union B is another set that we need to determine...denoted by A U B..got this much..??
Somewhat .. :/
ok well...we start from the beginning...do u know what an set is??
I haven't learned it since 8th grade , so no ..
ok...so do u need the answer or the do u want to understand the solution
Both . xD I want to understand it mostly .
ok...a set is a collection of something...anything...like a set of books refer to a collection of books...similarly u can have numbers..or words..eg A={1,54,69,85,14} is a set of numbers...Ur question consists of two sets with numbers in it..
if you have a bag of pretzels, and a can of walnuts; the union of the bag of pretzels with the can of walnuts creates a new set composed of all the elements of both containers. might be a good way of looking at a UNION of sets
Even { A, B, 9, 5, J} is a set...now we come to operations on sets...
\[\{\text{amistre, amriju, satellite, sceenie}\}\] is the set of people who are in this post
I see now ,
Now lets say u r going somewhere with the books by publishers A, B, C, D...on another day...u take books of Publishers B,C,D,E...now u dont have two books of the same publisher...so if I know this and I've seen u on both days...I can assert that u have books of publishers A, B, C, D, E...even though I've seen u carrying B, C, D on both days...now the collection of books refer to the sets...lets say X={ A, B, C, D} and Y= { B, C, D, E}...so X U Y is { A, B, C, D, E}..thats u dont repeat the items if they are present in both sets...but u include them only once...
Oh okay . I see now .
So can u work out the answer..?? post it here
I got {1, 2, 3, 4, 5, 6, 7, 8, 9, 12, 15, 18}
correct dear..:)
Really ? C:
:)..u learnt it...Isn't it damn simple??
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