Question

Find the zeros of (-3(x^2)(e^-2x))+(3x(e^-2x))

Answer 1

\[-3x^2e^{-2x}+3xe^{-2x}=0\\
-3xe^{-2x}\left(x-1\right)=0\]
\(e^{-2x}\) is always positive, so you can divide both sides by it:
\[-3x(x-1)=0\]