Question

How do I work out the absolute value for vector u if u = (1, -2, 6)?

Answer 1

I need to use it in the equation \[u.v = \left| u \right|\left| v \right| \cos \theta \]

Answer 2

\[|u|=\sqrt{(u_x)^2+(u_y)^2+(u_z)^2}\]
its just a distance formula

Answer 3

square, add, sqrt

Answer 4

I remember now, yes, thanks again. :) This is work from the beginning of the year I am going over again.

Answer 5

good luck :)

you can also think of it as the sqrt of the dot product of u.u

Answer 6

Ok, cool, thanks :)