Question

How would I algebraicly find the x intercept of y=(2^-x)-1?

Answer 1

x-intercepts are points of the form \((x,0)\). So for this value of x, the value of y is 0. So you solve the following equation:
\[0=2^{-x}-1\]

Answer 2

I don't understad what to do after I get \[2^{-x} = 1\]

Answer 3

\[2^{-x}=\frac{1}{2^x}=1\]
which is the same as
\[1=2^x\]
easier?