"t is a real number and p = (x,y) is the point on the unit circle that corresponds to t. find the exact values of the six trigonometric functions of t."
(square root 3/2, 1/2) t would be pi/6, right? how would you solve this problem?

Question

"t is a real number and p = (x,y) is the point on the unit circle that corresponds to t. find the exact values of the six trigonometric functions of t." 
(square root 3/2, 1/2) t would be pi/6, right? how would you solve this problem?

anonymous · Answer

help 
omg

anonymous · Answer

ELP PLS

dumbcow · Answer

you are correct, angle is pi/6

cos(pi/6) = sqrt3/2
sin(pi/6) = 1/2

tan = sin/cos

sec = 1/cos
csc = 1/sin
cot = 1/tan

anonymous · Answer

i don't understand how to do that, how do i find sec csc and cot?

anonymous · Answer

sin(pi/6) = 1/2 ; cos(pi/6) = (square root 3/2) ; tan(pi/6) = 1/square root 3 over 2/2 ????