Question

9|9 – 8x| = 2x + 3

Answer 1

these are tricky because you have to work in cases
if \(9-8x>0\) then
\[9|9-8x|=9(9-8x)=81-72x\] but if \(9-8x<0\) then \(|9-8x|=8x-9\) and so
\[9|9-8x|=9(8x-9)=72x-81\]

Answer 2

let's assume \(9-8x>0\) i.e. assume \(x<\frac{9}{8}\)
then solve
\[81-72x=2x+3\] what do you get ?

Answer 3

if it is not clear let me know and we can walk through it

Answer 4

you go this?

Answer 5

I got this now thank you so much! @satellite73

Answer 6

yw
there are two solution, neither of which are nice integers, both of which are fractions