Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

ah

OpenStudy (anonymous):

Umm well i got an answer but im not sure if its correct its a pretty big number

OpenStudy (anonymous):

The answer i got is 4595149970

OpenStudy (anonymous):

to begin with, you would want to simplify the numbers in radicals. rad(56) -> 6rad(14) rad(24) -> 2rad(6) rad(126) -> 3rad(14) rad(54) -> 3rad(6) 3*6rad(14)-7*2rad(6)-3rad(14)+4*3rad(6)

OpenStudy (anonymous):

18rad(14)-14rad(6)-3rad(14)+12rad(6)

OpenStudy (anonymous):

and you can think rad(14) and rad(6) as variables (x,y) So, the answer would be 3rad(14)-2rad(6)

OpenStudy (anonymous):

the third one. and my bad, it's 6, not 18.

OpenStudy (anonymous):

sure

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!